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Q.

In a carnot engine, the temperature of reservoir is $527 ° C$ and that of $sink$ is $200 K$ . If the workdone by the engine when it transfers heat from reservoir to sink is $12000 kJ$ , the quantity of heat absorbed by the engine from reservoir is ________ $\times 10^{6} J$

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answer is 16.

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Detailed Solution

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$(T_{2}) T_{sink} = 200 K (T_{1}) T_{Reservair} = 527 + 273 = 800 K W = 12000 K J = 12 \times 10^{6} J Q_{1} = ? η = 1 - \frac{T_{2}}{T_{1}} = \frac{W}{Q_{1}} = 1 - \frac{200}{800} = \frac{12 \times 10^{6}}{Q_{1}} \frac{3}{4} = \frac{12 \times 10^{6}}{Q_{1}} = Q_{1} = 16 \times 10^{6} J$

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In a carnot engine, the temperature of reservoir is 527°C and that of sink is 200 K. If the workdone by the engine when it transfers heat from reservoir to sink is 12000 kJ, the quantity of heat absorbed by the engine from reservoir is ________×106 J