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Q.

In a CE transistor amplifier, when a signal of 25 mV is added to the base-emitter voltage, the collector current changes by 2 mA. If the load resistance is $5 k Ω$ the voltage gain of the amplifier is

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a

100

b

400

c

10

d

25

answer is D.

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Detailed Solution

Voltage gain

$A_{v} = \frac{i_{c} R_{L}}{V_{i n}} = \frac{5 \times 10^{3} \times 2 \times 10^{- 3}}{25 \times 10^{- 3}} = 400$

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In a CE transistor amplifier, when a signal of 25 mV is added to the base-emitter voltage, the collector current changes by 2 mA. If the load resistance is 5 kΩ the voltage gain of the amplifier is