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In a certain electronic transition in the hydrogen atoms from an initial state (a) to final state (b) the difference in the orbit radius $(r_{1} - r_{2})$ is 24 times the first Bohr radius. Identify the transition

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$5 \to 1$

$6 \to 5$

$25 \to 1$

$8 \to 3$

answer is A.

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Detailed Solution

Let's think about the issue.

$Radius \propto \frac{n^{2}}{Z}$

For

$r_{n 2} - r_{n 1} = 24 \times r_{0}$

Since,

$n_{2}^{2} - n_{1}^{2} = 24$

Hence the solution is

$n_{2} = 7, n_{1} = 5 n_{2} = 5, n_{1} = 1$

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