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Q.

In a certain hypothentical radioactive decay process, species A decays into species B and species B decays into species C according to the reactions :

A2B+ particles +energy 

B2C+ particles +energy 

The decay constant for species is λ1=1sec1 and that for the species B is  λ2=100sec1 .Initially 104 moles of species of A were present while there was none of B and C. It was found that species B reaches its maximum number at a time t0=2 ln(10)sec. Calculate the value of maximum number of moles of B.

 

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a

4

b

2

c

5

d

1

answer is B.

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Detailed Solution

dNAdt=λ1NA dNBdt=2λ1NAλ2NB ,

NB =maximum dNBdt=0

2λ1NA=λ2NBmax NBmax=2λ1λ2NA

NBmax=2λ1λ2N0eλ1t=2

 

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