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In a certain operation 358 g of TiCl₄ is reacted with 96 g of Mg. Calculate % yield of Ti if 32 g of Ti is actually obtained [At. wt. Ti = 48, Mg = 24].

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60 %

35.46 %

100 %

66.6 %

answer is A.

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Detailed Solution

$Ti : {Cl}_{4} + 2 Mg \to 2 Mg {Cl}_{2} + Ti$

1.88 mol 4 mol

(L.R)

$\frac{32}{1.88 \times 48} \times 100$

$= 35.46 %$ 9 yieid

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