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In a certain town, 40% of the people have brown hair, 25% have brown eyes, and l5% have both brown hair and brown eyes. If a person selected at random from the town has brown hair, the probability that he also has brown eyes is

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answer is B.

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Detailed Solution

We have,
$\begin{array}{l} P (A) = \frac{40}{100}, P (B) = \frac{25}{100} and P (A \cap B) = \frac{15}{100} \\ so, P (\frac{B}{A}) = \frac{P (A \cap B)}{P (A)} = \frac{15 / 100}{40 / 100} = \frac{3}{8} \end{array}$

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