In a chemical equilibrium, the rate constant for the backward reaction is 7.5 × 10-4 and the equilibrium constant is 1.5 the rate constant for the forward reaction is

K=rfrb ⇒ 1.5 = rf7.5 × 10-4 ⇒ rf=1.12 × 10-3

K=rfrb ⇒ 1.5 = rf7.5 × 10-4 ⇒ rf=1.12 × 10-3

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In a chemical equilibrium, the rate constant for the backward reaction is $7.5 \times 10^{- 4}$ and the equilibrium constant is 1.5 the rate constant for the forward reaction is

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$9.0 \times 10^{- 4}$

$5 \times 10^{- 4}$

$2 \times 10^{- 3}$

$1.12 \times 10^{- 3}$

answer is C.

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$K = \frac{r_{f}}{r_{b}} \Rightarrow 1.5 = \frac{r_{f}}{7.5 \times 10^{- 4}} \Rightarrow r_{f} = 1.12 \times 10^{- 3}$

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