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Q.

In a circle with centre ‘O’ OM and ON are the perpendicular distances of the chords AB and CD from the centre ‘O’ and ON>OM , then the relation between chord AB and chord CD is

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a

AB=CD

b

AB>CD

c

AB<CD

d

AB=2CD

answer is B.

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Detailed Solution

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ON>OM

Chord length CD< chord length AB

CD<AB

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