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Q.

In a circle with centre ‘O’ OM and ON are the perpendicular distances of the chords AB and CD from the centre ‘O’ and $O N > O M$ , then the relation between chord AB and chord CD is

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a

A B = C D

b

A B > C D

c

A B < C D

d

A B = 2 C D

answer is B.

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Detailed Solution

Question Image

$O N > O M$

Chord length $C D <$ chord length AB

$C D < A B$

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In a circle with centre ‘O’ OM and ON are the perpendicular distances of the chords AB and CD from the centre ‘O’ and ON>OM , then the relation between chord AB and chord CD is