In a circle of diameter  $44 cm$, the length of a chord is 22cm. What is the length of minor arc of the chord?

 

Concept: A chord is a line segment that connects any two points on a circle's circumference. The perpendicular from the centre of a circle bisects the chord.

Here, diameter $=44 cm$

Radius $\frac{Diameter}{2}=\frac{44}{2}=22 cm$

Chord length $=22 cm$

In triangle  $∆AOB$, 

$OA=OB=Radius=22 cm$

$AB=22 cm$

Here, all sides are equal.

Thus, the triangle is equilateral and all angles will be same.

So, 

$\theta ={60}^{ }$

Now, Length of arc  $=\frac{\theta }{360}\times 2\mathrm{\pi r}$

$=\frac{60}{360}\times 2\times \frac{22}{7}\times 22$

$\frac{1}{6}\times \frac{968}{7}=\frac{484}{21} cm$

Hence, the length of minor arc of the chord is $\frac{484}{21} cm$.