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Q.

In a circuit there are two resistors of 3  and an unknown resistor and they are connected in series across a 12 V battery. If the potential difference across the unknown resistor is 6 V then the equivalent resistance of the circuit is [[1]] Ω.


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Detailed Solution

If a circuit contains two resistors of 3 Ω each and an unknown resistor connected in series across a 12 V battery and the potential difference across the unknown resistor is 6 V then the equivalent resistance of the circuit is 12 Ω.
It is given that two resistors, one of unknown resistance and the other of 3 Ω is connected in series combination across a 12 V battery.
Let the potential difference across the 3  resistance be V1. Therefore, the total resistance is equal to
   12=6+V1+V1
  6=2V1
V1=3V
The potential difference across the 3  resistance is 3 V.
Now, from the Ohm’s law, the current in the resistor 3  is
     I=VR
I=33
 I=1 A
Hence, the current in the 3  resistor is 1 A.
Since all the resistors are connected in series connection, the current in the unknown resistor is also 1 A.
The value of resistance such that the potential difference across the unknown resistor is 6 V and the current flowing through it is 1 A is
    R=VI
R=61
R=6 
Since the resistors are connected in series therefore equivalent resistance of the circuit id
     RS=3+3+6
RS=12 
Hence, the equivalent resistance of the circuit is 12 .
 
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