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In a class there are 10 men and 20 women. Out of them half the number of men and half the number of women have brown eyes. Out of them if a person is chosen at random the probability for the person chosen to be a man or a brown eyed person is

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1/3

2/3

1/15

2/5

answer is C.

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Detailed Solution

$E_{1} =$ Sel person is man

$E_{2} =$ Sel person is brown eyed person

$\begin{array}{rcl} P (E_{1}) & = & \frac{10}{30} P (E_{2}) = \frac{15}{30} P (E_{1} \cap E_{2}) = \frac{5}{30} \\ P (E_{1} \cup E_{2}) & = & \frac{10}{30} + \frac{15}{30} - \frac{5}{30} = \frac{20}{30} = \frac{2}{3} \end{array}$

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