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Q.

In a closed organ pipe, the frequency of fundamental note is 30 Hz. A certain amount of water is now poured into the organ pipe so that the fundamental frequency is increased to 110 Hz. If the organ pipe has a cross-sectional area of $2 {cm}^{2}$ , the volume of water poured in the organ tube is _______ ${cm}^{3}$ . (Take speed of sound in air is 330 m/s)

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a

600

b

400

c

300

d

500

answer is C.

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Detailed Solution

$n = \frac{V}{4 l} \Rightarrow l_{1} = \frac{330}{4 \times 30} a n d l_{2} = \frac{330}{4 \times 10}$

Volume of water poured $= (l_{1} - l_{2}) A$

$= (2.75 - 0.75) \times 2 \times 20^{- 4} m^{3} = 400 c m^{3}$

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In a closed organ pipe, the frequency of fundamental note is 30 Hz. A certain amount of water is now poured into the organ pipe so that the fundamental frequency is increased to 110 Hz. If the organ pipe has a cross-sectional area of 2 cm2 , the volume of water poured in the organ tube is _______ cm3. (Take speed of sound in air is 330 m/s)