Q.

In a closed organ pipe, the frequency of fundamental note is  30Hz. A certain amount of water is now poured in the organ pipe so that the fundamental frequency is increased to 110Hz . If the organ pipe has a cross – sectional area of 2cm2 . The amount of water poured in the organ tube is (velocity of sound is 330 m/s) 

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a

400 gm

b

200 gm

c

300 gm

d

600 gm

answer is B.

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Detailed Solution

V4l1=30
 1=114 V42=110
 2=34 Δ=2m m=ρ(ΔV) =ρ(AΔ) =1×2×200 =400g

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