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In a common - emitter configuration transistor amplifier, the load resistance of the output circuit is 1000 times the resistance of the input circuit, then the voltage gain is ( $α$ = 0.98)

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490

4900

49000

answer is D.

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Detailed Solution

voltage gain

$\begin{array}{rcl} A_{v} & = & β \frac{R_{L}}{R_{b}} b u t β = \frac{α}{1 - α} = \frac{0.98}{1 - 0.98} = 49 \\ A_{V} & = & 49 \times 1000 = 49000 \end{array}$

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