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In a compound C, H, N atoms are present in 9 : 1 : 3.5 by weight. Molecular weight of compound is 108. Its molecular formula is

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$C_{2} H_{6} N_{2}$

$C_{3} H_{4} N$

$C_{6} H_{8} N_{2}$

$C_{9} H_{12} N_{3}$

answer is C.

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Detailed Solution

9 + 1 + 3.5 = 13.5

$\begin{array}{l} ∵ 13 .5 g of compound contains \frac{9}{12} moles of carbon \\ ∴ 108 g of compound contains \frac{9 \times 108}{12 \times 13 .5} \\ = 6 mole carbon, i . e ., C_{6} H_{8} N_{2} \end{array}$

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