In a compound microscope, the focal lengths of two lenses are 1.5 cm and 6.25 cm .An object is placed at 2 cm from objective and the final image is formed at 25 cm from the eye lens. The distance between the two lenses is (in cm)

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7.75

9.25

answer is D.

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Detailed Solution

Length of tube L = v₀ + u_e

$\frac{1}{f_{0}} = \frac{1}{v_{0}} - \frac{1}{u_{0}} \frac{1}{1.5} = \frac{1}{v_{0}} + \frac{1}{2} v_{0} = 6 cm \frac{1}{6.25} = \frac{1}{- 25} - \frac{1}{u_{0}} u_{0} = 5 cm L = 6 + 5 = 11 cm$

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