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Q.

In a compound microscope, the focal lengths of two lenses are 1.5 cm and 6.25 cm an object is placed at 2 cm from objective and the final
image is formed at 25 cm from the eye lens. The distance between the two lenses is (in cm)

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a

6

b

7.75

c

9.25

d

11

answer is D.

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Detailed Solution

$\begin{aligned} \frac{1}{v_{0}} - \frac{1}{(- 2)} = \frac{1}{1.5} \\ \frac{1}{v_{0}} = \frac{1}{(6)} \Rightarrow v_{0} = 6 cm \\ B y u \sin g t u b e l e n g t h f o r m u l a f o r t h e M i c r o s c o p e : \\ \begin{aligned} L = v_{0} + \frac{Dfe}{D + fe} \\ \Rightarrow 6 + \frac{25 \times 6.25}{31.25} = 6 + 5 = 11 cm \end{aligned} \end{aligned}$

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In a compound microscope, the focal lengths of two lenses are 1.5 cm and 6.25 cm an object is placed at 2 cm from objective and the finalimage is formed at 25 cm from the eye lens. The distance between the two lenses is (in cm)