In a compound XY₂O₄, oxide ions are arranged in CCP and cations X are present in octahedral voids. Cations Y are equally distributed between octahedral and tetrahedral voids. The fraction of the octahedral voids occupied is

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answer is A.

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Detailed Solution

Oxide ions are arranged in CCP, i. e = 4 O^-2

Number of octahedral voids = 4

Number of tetrahedral voids = 8

According to Formula XY₂O₄

Number of cations X per unit cell =1 X

Number of cations Y per unit cell =2 Y

Cations Y are equally distributed between octahedral and tetrahedral voids, that means 1 cation Y is present in octahedral voids and 1 Y cation present in tetrahedral void.

The fraction of the octahedral voids occupied is = 1/2

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