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In a compound $X Y_{2} O_{4}$ , oxide ions are arranged in ccp structure. Cations X are present in octahedral voids and cations Y are equally distributed between octahedral and tetrahedral voids. The fraction of the octahedral voids occupied is

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$\frac{1}{6}$

$\frac{1}{8}$

$\frac{1}{2}$

$\frac{1}{4}$

answer is B.

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Detailed Solution

$O^{2 -}$ occupies ccp $∴ O^{2 -}$ is equal to $8 \times \frac{1}{8} + 6 \times \frac{1}{2} = 4$

‘X’ is present in O Voids

‘Y’ is present in T Voids as well as O Voids

Therefore, 2 atoms are present in O voids. So, fraction of octahedral voids occupied is equal to $= \frac{1}{2}$

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