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Q.
In a concave mirror when the object is located beyond C the magnification is?
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a
Less than 1
b
Greater than 1
c
Equal to 1
d
None of the above
answer is A.
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Detailed Solution
Concept: A hollow spherical can be made into a mirror by cutting it into pieces, painting the exterior surface of each piece, and using the inside surface as the reflecting surface. This kind of mirror is known as a concave mirror.
Linear magnification is the ratio of image length to object length measured in planes perpendicular to the optical axis (also called lateral or transverse magnification). A negative linear magnification value is used to represent inverted images.
If the item is outside the centre of curvature, the picture will still be centred somewhere between the focus point and the centre of curvature. No matter where the object is exactly, the picture will be in the chosen area. In this situation, the outcome would be an inverted image. That is to say, the image would be upside down if the object were upright.
In this instance, the image has shrunk, meaning that its dimensions are smaller than those of the item. If the item is a six-foot tall person, the image is not that tall. In this case, the absolute value of the magnification is less than one. A true image is created. The diagram below shows how the picture of the object outside the centre of curvature is formed.
When an object is positioned beyond C in a concave mirror, the magnification is less than one since the image created is smaller than the object.
Hence, option 1 is the correct answer.
Linear magnification is the ratio of image length to object length measured in planes perpendicular to the optical axis (also called lateral or transverse magnification). A negative linear magnification value is used to represent inverted images.
If the item is outside the centre of curvature, the picture will still be centred somewhere between the focus point and the centre of curvature. No matter where the object is exactly, the picture will be in the chosen area. In this situation, the outcome would be an inverted image. That is to say, the image would be upside down if the object were upright.
In this instance, the image has shrunk, meaning that its dimensions are smaller than those of the item. If the item is a six-foot tall person, the image is not that tall. In this case, the absolute value of the magnification is less than one. A true image is created. The diagram below shows how the picture of the object outside the centre of curvature is formed.
Hence, option 1 is the correct answer.
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