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In a conductivity cell the two platinum electrodes, each of area 10 sq. cm is fixed 1.5 cm apart. The cell contained 0.05 N solution of a salt. If the two electrodes are just half dipped into the solution which has a resistance of $50 Ω$ , find equivalent conductance of the salt solution

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$120 {S cm}^{2} {eq}^{- 1}$

$160 {S cm}^{2} {eq}^{- 1}$

$125 {S cm}^{2} {eq}^{- 1}$

$120 {S m}^{2} {eq}^{- 1}$

answer is A.

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Detailed Solution

$50 = \frac{1}{Λ_{eq}} \times \frac{1 .5}{10 / 2} \times \frac{1000}{0 .05} \Rightarrow λ_{eq} = 120 S {cm}^{2} {eq}^{- 1}$

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