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In a constant pressure calorimeter, 224 mL of 0.1 M KOH (aq) solution is reacted with 50 mL of 0.1 M $H_{2} {SO}_{4}$ (aq) solution then increase in temperature of solution will be (assume heat capacity of calorimeter is negligible)
Given : Specific heat of solution= 1 cal/g - K
Density of solution = 1 g/mL

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0 5 K

1 K

2 K

4 K

answer is A.

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Detailed Solution

$2 KOH + H_{2} {SO}_{4} ⟶ K_{2} {SO}_{4} + H_{2} O$

$\begin{array}{lc} 0.224 \times 0.1 & \frac{50}{1000} \times 0.1 \\ = 2.24 \times 10^{- 2} & 5 \times 10^{- 3} \\ - & (LR) \end{array}$

Total mass of solution $= (224 + 50) x 1$

$\begin{array}{l} 274 \times 1 \times Δ T = 13.7 \times 2 \times 5 \times 10^{- 3} \times 1000 \\ Δ T = \frac{137}{274} = 0.5 K \end{array}$

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