In a cricket match, a batswoman hits a boundary 6 times out of 30 balls she plays. Find the probability that she did not hit a boundary.

No. of balls she played n(S) = 30

No.of balls went on a boundary = 6

No. of balls did not hit the boundary n(A) $=30-6=24$

The probability $p\left(A\right)=\frac{n\left(A\right)}{n\left(s\right)}$

Thus, the probability that she did not hit a boundary$=\frac{24}{30}=\frac{4}{5}.$