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In a crystalline solid, anions B are arranged in ccp lattice and cations A occupy 50% of the octahedral voids and 50% of the tetrahedral voids. What is the formula of the solid ?

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A₂B₃

AB₂

A₃B₂

answer is B.

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Detailed Solution

No of atoms in a CCP unit cell=similar to FCC=4
Therefore, no of B atoms present=4
No of A atoms=tetrahedral void and octohedral void (4+2) =6
The formula of the compound = A₃B₂

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