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In a cubical hall ABCDPQRS with each side 10m, G is the centre of the wall BCRQ and T is the mid-point of the side AB. The angle of elevation of G at the point T is

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sin − 1 13

cos − 1 13

cot − 1 13

tan − 1 (3)

answer is A.

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Detailed Solution

Let H be the mid point of BC
Since $∠ T B H = 90^{\circ}$ then $T H 2 = B T 2 + B H 2 = 52 + 52 = 50$
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$∠ T B H = 90^{\circ}$

$T G 2 = T H 2 + G H 2 = 50 + 25 = 75$ ,

Let $θ$ be the required angle of elevation of G at T

then $sin θ = G H T G = 553 = 13$

$θ = sin − 1 13$

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