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In a cyclotron, the final radius of the circular path of a proton beam is 1.5 metres. If the magnetic induction is 0.15T, the energy of the emitted protons is ..... MeV

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2.53

34.2

43.2

23.4

answer is C.

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Detailed Solution

$E = \frac{r^{2} q^{2} B^{2}}{2 m} = 0.0405 \times 10^{- 11} J = 2.5 MeV$

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