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Q.

In a diffraction pattern due to a single slit of width 'a', the first minimum is observed at an angle 30° when light of wavelength 5000 Å is incident on the slit. The first secondary maximum is observed at an angle of:

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a

sin−1⁡23

b

sin−1⁡34

c

sin−1⁡14

d

sin−1⁡12

answer is D.

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Detailed Solution

For the first minima, θ=ηλa⇒sin⁡30∘=λa=12

First secondary maxima will be at 

sin θ=3λ2a=32x12⇒θ=sin−134

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