Q.

In a diffraction pattern due to a single slit of width a, the first minimum is observed at an angle 300 when light of wavelength 5000 A0 is incident on the slit. The first secondary maximum is observed at an angle of sin1x4 then x is

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answer is 3.

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Detailed Solution

asinθ=nλ

asin30=λ

a=2λ

asinθ1=32λ

2λsinθ1=32λ

sinθ1=34

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