In a double-slit experiment, at a certain point on the screen the path difference between the two interfering waves is 14th of a wave length. The ratio of intensity of light at that point to that at the centre of a bright fringe is

Δx=d4 Δq=2ΠhΔx=2Πh=Π2 I=Iocos2(Δq2) IIo=Cos2(Π/24)=12=0.5

In a double-slit experiment, at a certain point on the screen the path difference between the two interfering waves is 14th of a wave length. The ratio of intensity of light at that point to that at the centre of a bright fringe is

Δx=d4 Δq=2ΠhΔx=2Πh=Π2 I=Iocos2(Δq2) IIo=Cos2(Π/24)=12=0.5

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In a double-slit experiment, at a certain point on the screen the path difference between the two interfering waves is $\frac{1}{4}$ ^th of a wave length. The ratio of intensity of light at that point to that at the centre of a bright fringe is

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0.85

0.60

0.50

0.76

answer is C.

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$Δ x = \frac{d}{4} Δ q = \frac{2 Π}{h} Δ x = \frac{2 Π}{h} = \frac{Π}{2} I = I_{o} \cos^{2} (\frac{Δ q}{2}) \frac{I}{I_{o}} = C o s^{2} (\frac{Π / 2}{4}) = \frac{1}{2} = 0.5$

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In a double-slit experiment, at a certain point on the screen the path difference between the two interfering waves is 14th of a wave length. The ratio of intensity of light at that point to that at the centre of a bright fringe is

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In a double-slit experiment, at a certain point on the screen the path difference between the two interfering waves is $\frac{1}{4}$ ^th of a wave length. The ratio of intensity of light at that point to that at the centre of a bright fringe is