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In a double slit experiment, instead of taking slits of equal widths, one slit is made twice as wide as the other. Then in the interference pattern,

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The intensity of maxima increases and the minima has zero intensity

The intensities of both the maxima and the minima increases

The intensity of maxima decreases and that of the minima increases

The intensity of maxima decreases and the minima has zero intensity

answer is A.

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Detailed Solution

$I_{m a x} \propto {(A_{1} + A_{2})}^{2}$

$I_{m a x, i} \propto {(A + A)}^{2} = 4 A^{2}$

$I_{m a x, f} \propto {(2 A + A)}^{2} = 9 A^{2} = \frac{9}{4} I_{m a x, i}$

$I_{m i n} \propto {(A_{1} - A_{2})}^{2}$

$I_{m i n, i} \propto {(A - A)}^{2} = 0$

$I_{m i n, f} \propto {(2 A - A)}^{2} = A^{2} = I > 0$

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