In a double slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic light of wavelength 500 mm is used. What will be the width of each slit for obtaining tenth maxima of double slit within the central maxima of single slit pattern ?

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0.5 mm

0.2 mm

0.1 mm

0.02 mm

answer is C.

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Detailed Solution

Distance between two slits
d=1mm=10^-3mm ; D=1m
$λ = 500 \times 10^{- 9} m$ Width of each slit a = Width of central maxima in single slit pattern
$\begin{array}{l} = \frac{2 λD}{a}; Condition is \frac{10 λD}{d} = \frac{2 λD}{a} \\ a = \frac{d}{5 D} = \frac{1}{5} \times 10^{- 3} m; a = 0 .2 mm \end{array}$

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