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In a face centred cubic lattice, atom A occupies the corner positions and atom B occupies the face centred positions. If one atom of B missing from one of the face centred points, the formula of the compound is

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A₂B

A₂B₃

AB₂

A₂B₅

answer is D.

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Detailed Solution

Number of atoms of A = $8 \times \frac{1}{8} = 1$

Number of atoms of B = $5 \times \frac{1}{2} = \frac{5}{2}$

$A : B = 1 : \frac{5}{2} = 2 : 5 Formula of the solid = A_{2} B_{5}$

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