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In a first order reaction, the concentration of the reactant, decreases from 0.8 M to 0.4 Min 15 minutes. The time taken for the concentration to change from 0.1 M to 0.025 M is

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Detailed Solution

The decrease of concentration from 0.8 M to 0.4 M implies that $t_{1 / 2} = 15 \min$ . The change in concentration from 0.1 M to 0.025 M will require two half-lives. Hence $t = 2 t_{1 / 2} = 30 \min .$

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