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In a first order reaction the reacting substance has half-life period often minutes. What fraction of the substance will be left after an hour the reaction has occurred?

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$\frac{1}{6}$ of initial concentration

$\frac{1}{64}$ of initial concentration

$\frac{1}{12}$ of initial concentration

$\frac{1}{32}$ of initial concentration

answer is B.

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Detailed Solution

Given in a first order reaction the reacting substance has half-life period often minutes. In this case, fraction of the substance will be left after an hour the reaction has occurred. Thus,

$[A]_{t} = \frac{a}{2^{6}} = \frac{a}{64}$

So the fraction will be 1/64.

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