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Q.

In a Fraunhofer diffraction at single slit of width d with incident light of wavelength 5500 Å, the first minimum is observed, at angle 30°. The first secondary maximum is observed at an angle θ= 

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a

sin-114

b

sin-132

c

sin-134

d

sin-112

answer is C.

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Detailed Solution

Slit width =d 

λ= 5500 Å=5.5×10-7 m, θ1=30°

For first secondary minima, d sinθ1=λ

d=λsin θn=5.5×10-7sin 30°=11×10-7 m

For first secondary maxima, dsinθ=3λ2

i.e. sinθ=3λ2d=3×5.5×10-72×11×10-7

sinθ=34     θ=sin-134

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