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Q.

In a Fraunhofer diffraction experiment at a single slit using a light of wavelength 400 nm, the first minimum is formed at an angle 30∘. The direction θ of the first secondary maximum is given by:

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a

sin−1(34)

b

sin−1(23)

c

sin−1(14)

d

sin−1(25)

answer is B.

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Detailed Solution

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For first diffraction minimum asinθ'=λ⇒a=λsinθ'

For first secondary maximum, we use,

 asinθ=3λ2

sinθ=3λ2×1a=3λ2×sinθ'λ

sinθ=32×sin30o=34

θ=sin−1(34)

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