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In a game, a pair of dice is rolled 25 times.If a person wins the game by not getting 6 on both the dice in any one of the 24 rolls , then the probability that a person wins the game is

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${(\frac{35}{36})}^{24}$

${(\frac{17}{18})}^{24}$

${(\frac{11}{12})}^{24}$

${(\frac{5}{6})}^{24}$

answer is A.

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Detailed Solution

If two dies are rolled will getting 6 on both dies is $= \frac{1}{36}$

Not getting 6 on both the dies is $= \frac{35}{36}$

Pair of dies rolled 25 times,E is the event a person wins the game by not getting 6 on both the dice

in any one of 24 rolles is $= {(\frac{35}{36})}^{24}$

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