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Questions  

In a geometric progression the ratio of the sum of the first 5 terms to the sum of their reciprocals is 49 and sum of the first and the third term is 35.The fifth term of the G.P. is

a
7
b
7/2
c
7/4
d
7/8

detailed solution

Correct option is C

Let five terms in G.P. be ar2, ar, a, ar, ar2

Then ar2+r1+1+r+r2(1/a)r2+r+1+r1+r2=49

 a2=49a=±7.

Also, ar2+a=35

Therefore a =  7 is not possible

Thus, a=7 and a/r2=28.

Now, fifth term =ar2=aa28=74

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