Q.

In a Germanium diode, the forward current increases from 100 mA, to 200 mA, when forward voltage changes from 5 V to 10 V. The forward resistance of the diode is _______Ω.

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answer is 50.

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Detailed Solution

V=1R
 R=V1=5100mA=5100×103R=50Ω
 
 

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