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Q.

In a given process on an ideal gas, dW = 0 and dQ < 0. Then for the gas

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a

the temperature will decrease

b

the volume will increase

c

the pressure will remain constant

d

the temperature will increase

answer is A.

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Detailed Solution

According to first law of thermodynamics,
$dQ = dU + dW$
When $dW = 0 and dQ < 0$ , then $dU < 0$
i.e., the temperature will decrease.

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In a given process on an ideal gas, dW = 0 and dQ < 0. Then for the gas