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Q.

In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6Hz. When tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be 

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a

524 Hz

b

523 Hz

c

536 Hz

d

537 Hz

answer is A.

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Detailed Solution

In case of beats formation, unknown frequency, 

vB=vA± beats 

where,   vA=530Hz and beats =6Hz

∴ vB=530±6=536Hz or 524Hz

When tension in B is slightly decreased, then beat frequency increases to 7 Hz. This is possible, if we take original frequency of B as 524 Hz.

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