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In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6Hz. When tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be

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524 Hz

523 Hz

536 Hz

537 Hz

answer is A.

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Detailed Solution

In case of beats formation, unknown frequency,

$v_{B} = v_{A} \pm beats$

where, $v_{A} = 530 Hz and beats = 6 Hz$

$∴ v_{B} = 530 \pm 6 = 536 Hz or 524 Hz$

When tension in B is slightly decreased, then beat frequency increases to 7 Hz. This is possible, if we take original frequency of B as 524 Hz.

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