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In a horizontal pipe line of uniform area of cross-section, the pressure falls by $8 N m^{- 2}$ between two points separated by distance of $1 k m$ . The change in KE $p e r k g$ of the oil flowing at these points is (density of oil is $800 k g / m^{3}$ )

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$10^{- 2} J k g^{- 1}$

$10^{- 5} J k g^{- 1}$

$10^{2} J k g^{- 1}$

$10^{- 3} J k g^{- 1}$

answer is A.

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Detailed Solution

For horizontal pipe

Change in KE per unit mass $= \frac{p_{1} - p_{2}}{ρ}$ $= \frac{8}{800} = 10^{- 2} J / k g$

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