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Q.

In a hospital, the ages of diabetic patients were recorded as follows.


Age (in years)

No. of patients

0-15

5

15-30

20

30-45

40

45-60

50

60-75

25


The median age is ____ years.


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Detailed Solution

In a hospital, the ages of diabetic patients were recorded as follows.

Age (in years)

No. of patients

0-15

5

15-30

20

30-45

40

45-60

50

60-75

25

The median age is 46.5 years.
Given:

Age (in years)

No. of patients

0-15

5

15-30

20

30-45

40

45-60

50

60-75

25

Formula used:
 Median =l+ h× N 2 cf f   , where l=   lower limit of the median class, h=   size of the median class, f=   frequency of the median class, N=   the sum of frequencies and c.f.   cumulative frequency of the class just preceding the median class.
The cumulative frequency table:

Age (in years)

No. of patients

Cumulative Frequency

0-15

5

5

15-30

20

5+20=25

30-45

40

25+40=65

45-60

50

65+50=115

60-75

25

105+25=140

Here,
  N=140 N 2 = 140 2 N 2 =70   The cumulative frequency just greater than 70 is 115 and the corresponding class is 45-60.
Therefore, the median class is 45-60.
l=45,h=15,f=50,N=140 and cf=65  
Substitute the values in the formula:
 Median  =l+ N 2 cf f ×h  Median  =45+ 7065 50 ×15 =45+1.5 =46.5  
Hence, the median age is 46.5 years.
 
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