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In a hot water heating system, there is a cylindrical pipe of length 28m, and diameter 5cm. Find total radiating surface in the system.

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4.4 m2

6.6 m2

3.3 m2

5.5 m2

answer is C.

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Detailed Solution

Given a cylindrical pipe of length 28m and diameter 5cm.
We know the radius is half of the diameter. So,

r = d 2

⇒ 52 cm

⇒ 2.5

cm
1 cm=

1100

⇒ 2.5 100 m

⇒ 0.025 m

The total radiating surface = the curved surface area of the cylinder.
CSA =

2 π r h

Substitute values,

⇒ 2 × 227 × 0.025 m × 28 m

⇒ 4.4 m 2

The total radiating surface is 4.4 m2.
Therefore, the correct option is 3.

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