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In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating in the system.

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40073.98 {cm}^{2}

300039.28 {cm}^{2}

40009.28 {cm}^{2}

44039.28 {cm}^{2}

answer is D.

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Detailed Solution

Given
Diameter = 5 cm
r = radius = Diameter/2 = 2.5 cm h= height of the cylinder = length of the cylinder
Question Image

Length of cylindrical pipe = 28 m = 2800 cm. (since, 1 m = 100 cm)
Total radiating surface of pipe = Curved surface area + 2

\times

Area of circular crossection

= 2 πrh + 2 π r^{2} = 2 πr (h + r) = 2 \times \frac{22}{7} \times 2.5 (2800 + 2.5)

= 44039.28 {cm}^{2}

Hence, the area of radiating surface

= 44039.28 {cm}^{2}

Correct option is 4.

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