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Q.

In a hotel, four rooms are available. Six persons are to be accommodated in these four rooms in such a way that each of these rooms contains at least one person and at most two persons.Then the number of all possible ways in which this can be done is k . Find the sum of the digits of k is ________

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answer is 9.

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Detailed Solution

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Number of persons in rooms will be 2, 2, 1, 1.
 So, required number of ways =6!2!2!1!1!2!2!×4!=1080

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