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In a hydel power project, 2000kg of water passes through the turbine every second. Water is falling from a height of 240m above ground. If the power output is 3.6 MW, the efficiency of the power house is (g= 10ms^-2)

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Correct option is B

$P = \frac{mgh}{t} = \frac{2000 \times 10 \times 240}{1} = 4.8 MW$
efficiency $= \frac{3.6}{4.8} \times 100 = 75 %$

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In a hydel power project, 2000kg of water passes through the turbine every second. Water is falling from a height of 240m above ground. If the power output is 3.6 MW, the efficiency of the power house is (g= 10ms-2)

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In a hydel power project, 2000kg of water passes through the turbine every second. Water is falling from a height of 240m above ground. If the power output is 3.6 MW, the efficiency of the power house is (g= 10ms^-2)