In a hydraulic lift, the surface area of the input piston is 6 cm2 and that of the output piston is 1500 cm2. If 100 N force is applied to the input piston to raise the output piston by 20 cm, then the work done is ________

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In a hydraulic lift, the surface area of the input piston is 6 cm² and that of the output piston is 1500 cm². If 100 N force is applied to the input piston to raise the output piston by 20 cm, then the work done is _________ kJ.

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answer is 5.

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Detailed Solution

$\begin{array}{l} \frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}}, \frac{100}{6} = \frac{F}{1500}, F = \frac{50}{3} \times 1500 \\ F = 50 \times 500 = 25 \times 10^{3} N \\ ω = \vec{F} . \vec{S} = 25 \times 10^{3} \times \frac{20}{100} \end{array}$
= 5 × 10³ = 5 kJ