In a hydrogen atom electron moves in an orbit of radius 5 × 10-11m with a speed of 2.2 × 106m/sec. Calculate the equivalent current.....

i=fe=V2πre=2.2×1062π×5×10−11×1.6×10−19=1.12×10−3amp=1.12mA

In a hydrogen atom electron moves in an orbit of radius 5 × 10-11m with a speed of 2.2 × 106m/sec. Calculate the equivalent current.....

i=fe=V2πre=2.2×1062π×5×10−11×1.6×10−19=1.12×10−3amp=1.12mA

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In a hydrogen atom electron moves in an orbit of radius 5 × 10^-11m with a speed of 2.2 × 10⁶m/sec. Calculate the equivalent current.....

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1.2 mA

1.16 mA

1.12 mA

1.1 mA

answer is C.

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Detailed Solution

$i = f (e) = \frac{V}{2 π r} (e) = \frac{2.2 \times 10^{6}}{2 π \times 5 \times 10^{- 11}} \times 1.6 \times 10^{- 19}$

$= 1.12 \times 10^{- 3} a m p = 1.12 m A$

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In a hydrogen atom electron moves in an orbit of radius 5 × 10-11m with a speed of 2.2 × 106m/sec. Calculate the equivalent current.....

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In a hydrogen atom electron moves in an orbit of radius 5 × 10^-11m with a speed of 2.2 × 10⁶m/sec. Calculate the equivalent current.....