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Q.

In a hydrogen like atom, when an electron jumps from the M-shell to the L-shell, the wavelength of emitted radiation is 'λ '. If an electron jumps from N-shell to the L-shell, the wavelength of emitted radiation will be: 

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a

2027λ

b

2516λ

c

1625λ

d

2720λ

answer is D.

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Detailed Solution

1λ1=R122−142=3R16

And 1λ=R122−132=5R36

Now λ1λ=5R/363R/16=2027

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